变限积分函数#

变限积分函数的连续性、可导性#

$$ \Phi(x)=\int_0^xf(x)dx $$ $$ 1. f(x)在[a,b]可积,\Phi(x)在[a,b]上连续\\ 2. f(x)在[a,b]连续,\Phi(x)在[a,b]上可导\\ 3. f(x)在[a,b]k阶可导,\Phi(x)在[a,b]上k+1阶可导 $$

变限积分函数在间断点的可导性#

$$ \Phi(x)=\int_a^xf(t)dt $$ $$ 若x_0是f(x)的可去间断点,则\Phi(x)在x_0处可导,且\\F'(x_0)=\lim\limits_{x\to x_0}f(x) $$

$$ 若x_0是f(x)的跳跃间断点,则\Phi(x)在x_0处连续,但不可导,且\\ F_-'(x_0)=\lim\limits_{x\to x_0^-}f(x),F_+'(x_0)=\lim\limits_{x\to x_0^+}f(x)\\ $$

$$ 注:可由洛必达证得 $$

变限积分函数的奇偶性、周期性#

前提:f(x)可积

$$ f(x)\ \ \ 奇 \Longrightarrow \int_a^xf(t)dt=\int_0^xf(t)dt-\int_0^af(t)dt \quad 偶 $$

$$ f(x)\ \ \ 偶 \left\{ \begin{array}{l} \Rightarrow\int_0^xf(t)dt\quad 奇\\ \\ \int_0^af(x)dx=0 \Rightarrow \int_a^xf(t)dt=\int_0^xf(t)dt\Rightarrow\int_a^xf(t)dt \quad奇\\ \end{array} \right. $$

$$ f(x)\ \ T \quad 且 \quad \int_0^T f(x)dx=0 \Longleftrightarrow \int_0^x f(t)dt \quad T $$

变限积分“被积函数含积分上限”情形#

加减型:

$$ \int_a^x(x-t)f(t)dt=x\int_a^xf(t)dt-\int_a^xtf(t)dt $$

复合型:

$$ \int_0^xtf(x^2-t^2)dt,令u=x^2-t^2,得\frac{1}{2}\int_0^{x^2}f(u)du $$

$$ \int_0^3x\sqrt{9-x^2t^2}\ dt \ \ \ 令u=xt, 得 \int_0^{3x}\sqrt{9-u^2}du\\ (注意\frac{1}{x}情形,需分类讨论)\\ \int_0^x[e^{(t-x)^2}-1]\sin t dt\quad 令u=t-x,得\int_{-x}^0[e^{u^2}-1]\sin(u+x)du\quad 拆\sin(u+x) $$

$$ 注:F(x)=\int_a^xf(x)+g(u)du\\ F'(x)=[f(x)(x-a)]'+g(x)\neq f(x)+g(x) $$

积分与函数比较大小#

$$ \int_{\frac{1}{x}}^1f(t)dt与g(x)(1-\frac{1}{x})\\ \begin{array}{ll} \int_{\frac{1}{x}}^1f(t)dt &\rightarrow f(\xi)(1-\frac{1}{x})\\ g(x)(1-\frac{1}{x})& \rightarrow \int_{\frac{1}{x}}^1g(x)dt \end{array} $$

小技巧#

$$ 巧用\int_a^x f(t)dt表示f(x)的原函数 $$